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Now I want to solve this integral by using the process of integration by substitution. I'll start by taking the constant out of the square root function and I get
Next I want to eliminate the square root. The form of the function under the radical gives me an almost obvious substitution that enables me to do just that: I define x/a=iSinθ, so that dx/a=iCosθdθ, and I get
I then invert the substitution,θ=Sin-1(x/ia), and get
which we got in the previous derivation. But we also know that
which we use in the following application.
In the x-z plane gravity operates in the negative z-direction and the x-axis, running horizontally, defines ground level. We set up a vertical pole of height z0 at the point x0 and set up a second vertical pole of height z1 at the point x1. Then we take a perfectly limp cord of uniform density along its length and of length L>x1-x0 and attach its ends to the tops of the poles, allowing it to hang free under its own weight. We want to derive a description of the cord's location, point by point, as a function z(x) on the domain between x0 and x1.
We say that each element ds of the cord's length has the weight wds. At any point on the cord the straight line tangent to the cord makes an angleϕ with the x-axis. At each and every point on the cord the tension T within the cord must point in the direction parallel to the tangent line at that point and, because the cord does not move, the forces acting on the cord at each and every point must balance. Thus we infer two facts:
1. The vertical component of the tension must change along the cord in a way that balances the weight of each differential segment of the cord; that is,
2. The horizontal component of the tension does not change; that is,
Equation 6 tells us immediately that
in which C represents a constant. We divide Equation 5 by that constant and then, noting that division by a constant commutes with the operation of differentiation, we substitute from Equation 7 to get
Referring to our desired function z(x) and the angle that the cord makes with the x-axis at any given point, we have
in which I have defined the upper-case zee for convenience in what follows. We also describe the length of the differential segment of the cord as
We thus have Equation 8 in the form
Dividing that equation by the radical and integrating gives us
If we solve that equation for Z, multiply the result by dx, and integrate, we get
which describes our cord as a catenary. The integration constants A, B, and C must take values that give the curve the correct values z(x0)=z0, z(x1)=z1, and length L, which we calculate from
in which I have replaced Z with the corresponding hyperbolic sine and used Cosh2ξ-Sinh2ξ=1 to set up the integration in the second line. I leave the actual determination of A, B, and C to the interested reader.
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